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Simple script to return or expand a shortURL link. It use Python.
It include more 20 different shortURL links provider.
If the link provider is not in the list set Force to True
Applescript:
set dialogText to "Paste the shortURL link:"
set theURLString to (display dialog dialogText default answer "https://apple.co/3oFQeDf")'s text returned
display alert (my expandShortURL:theURLString force:"False")
on expandShortURL:_theURL force:_bool
set theScript to "
import requests
from urlparse import urlparse, urljoin
URL_SHORTENERS = [
'bit.ly',
'ow.ly',
'dlvr.it',
'fb.me',
'4sq.com',
'is.gd',
'j.mp',
'tmblr.co',
'ibm.co',
'on.fb.me',
'vsb.li',
'shar.es',
'ht.ly',
'wp.me',
'dld.bz',
'n.pr',
'tiny.cc',
'ar.gy',
'adf.ly',
'lnkd.in',
'ow.ly',
'slidesha.re',
'bbc.in',
'flic.kr',
'bitly.com',
'wapo.st',
'aol.it',
'monk.ly',
'intel.ly',
'go.ign.com',
'twb.io',
'short.to',
's.co',
'youtu.be',
'tiny.cc',
'huff.to',
'on.mash.to',
'goo.gl',
'tinyurl.com',
'git.io',
'su.pr',
'rww.to',
'appd.it',
'on.cnn.com',
'trap.it',
'dlvr.it',
'zite.to',
'itsh.bo',
]
def resolve_short_url(url, force=False, depth=1):
domain = urlparse(url).netloc
if not force and len(domain) >= 7 and domain not in URL_SHORTENERS:
return url
count = 0
while count < depth:
count += 1
r = requests.head(url, allow_redirects=False)
if 'location' not in r.headers:
break
url = r.headers['location']
if url.startswith('//'):
parsed_rurl = urlparse(r.url)
url = '%s:%s' % (parsed_rurl.scheme, url)
if not urlparse(url).netloc:
url = urljoin(r.url, url)
return url
print resolve_short_url('" & _theURL & "', '" & _bool & "',1)
"
return (do shell script "python <<EOF" & theScript & "EOF") as text
end expandShortURL:force:
The purpose to study someone else art is not to add, its to make less more.
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